DLMF:15.4.E9 (Q4993): Difference between revisions

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DLMF:15.4.E9
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    F ( a , 1 2 + a ; 3 2 ; z 2 ) = 1 ( 2 - 4 a ) z ( ( 1 + z ) 1 - 2 a - ( 1 - z ) 1 - 2 a ) , Gauss-hypergeometric-F 𝑎 1 2 𝑎 3 2 superscript 𝑧 2 1 2 4 𝑎 𝑧 superscript 1 𝑧 1 2 𝑎 superscript 1 𝑧 1 2 𝑎 {\displaystyle{\displaystyle F\left(a,\tfrac{1}{2}+a;\tfrac{3}{2};z^{2}\right)% =\frac{1}{(2-4a)z}\left((1+z)^{1-2a}-(1-z)^{1-2a}\right),}}
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    DLMF:15.4.E9
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