DLMF:31.10#Ex3 (Q9058): Difference between revisions

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DLMF:31.10#Ex3
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    sin θ sin ϕ = ( ( z - 1 ) ( t - 1 ) 1 - a ) 1 / 2 . 𝜃 italic-ϕ superscript 𝑧 1 𝑡 1 1 𝑎 1 2 {\displaystyle{\displaystyle\sin\theta\sin\phi=\left(\frac{(z-1)(t-1)}{1-a}% \right)^{1/2}.}}
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    DLMF:31.10#Ex3
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