DLMF:12.14.E19 (Q4259): Difference between revisions

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Revision as of 16:17, 30 December 2019

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DLMF:12.14.E19
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    ω = 1 4 x 2 - a ln x + 1 4 π + 1 2 ϕ 2 , 𝜔 1 4 superscript 𝑥 2 𝑎 𝑥 1 4 𝜋 1 2 subscript italic-ϕ 2 {\displaystyle{\displaystyle\omega=\tfrac{1}{4}x^{2}-a\ln x+\tfrac{1}{4}\pi+% \tfrac{1}{2}\phi_{2},}}
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    DLMF:12.14.E19
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