DLMF:3.9.E5 (Q1390)

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DLMF:3.9.E5
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    ln 2 = 1 - 1 2 + 1 3 - 1 4 + = 1 1 2 1 + 1 2 2 2 + 1 3 2 3 + , 2 1 1 2 1 3 1 4 1 1 superscript 2 1 1 2 superscript 2 2 1 3 superscript 2 3 {\displaystyle{\displaystyle\ln 2=1-\frac{1}{2}+\frac{1}{3}-\frac{1}{4}+\cdots% =\frac{1}{1\cdot 2^{1}}+\frac{1}{2\cdot 2^{2}}+\frac{1}{3\cdot 2^{3}}+\cdots,}}
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    DLMF:3.9.E5
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    ln z 𝑧 {\displaystyle{\displaystyle\ln\NVar{z}}}
    C4.S2.E2.m2adec
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