DLMF:5.2.E3 (Q2028)

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DLMF:5.2.E3
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    Statements

    Defining formula
    γ = lim n → ∞ ⁡ ( 1 + 1 2 + 1 3 + … + 1 n - ln ⁡ n ) = 0.57721 56649 01532 86060 ⁢ … . subscript → 𝑛 1 1 2 1 3 … 1 𝑛 𝑛 0.57721 56649 01532 86060 … {\displaystyle{\displaystyle\gamma=\lim_{n\to\infty}\left(1+\frac{1}{2}+\frac{% 1}{3}+\dots+\frac{1}{n}-\ln n\right)=0.57721\;56649\;01532\;86060\;\dots.}}
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    DLMF:5.2.E3
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