DLMF:5.9.E18 (Q2107)

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DLMF:5.9.E18
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    γ = - 0 e - t ln t d t = 0 ( 1 1 + t - e - t ) d t t = 0 1 ( 1 - e - t ) d t t - 1 e - t d t t = 0 ( e - t 1 - e - t - e - t t ) d t . superscript subscript 0 superscript 𝑒 𝑡 𝑡 𝑡 superscript subscript 0 1 1 𝑡 superscript 𝑒 𝑡 𝑡 𝑡 superscript subscript 0 1 1 superscript 𝑒 𝑡 𝑡 𝑡 superscript subscript 1 superscript 𝑒 𝑡 𝑡 𝑡 superscript subscript 0 superscript 𝑒 𝑡 1 superscript 𝑒 𝑡 superscript 𝑒 𝑡 𝑡 𝑡 {\displaystyle{\displaystyle\gamma=-\int_{0}^{\infty}e^{-t}\ln t\mathrm{d}t=% \int_{0}^{\infty}\left(\frac{1}{1+t}-e^{-t}\right)\frac{\mathrm{d}t}{t}=\int_{% 0}^{1}(1-e^{-t})\frac{\mathrm{d}t}{t}-\int_{1}^{\infty}e^{-t}\frac{\mathrm{d}t% }{t}=\int_{0}^{\infty}\left(\frac{e^{-t}}{1-e^{-t}}-\frac{e^{-t}}{t}\right)% \mathrm{d}t.}}
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    DLMF:5.9.E18
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    γ {\displaystyle{\displaystyle\gamma}}
    C5.S2.E3.m2acdec
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    d x 𝑥 {\displaystyle{\displaystyle\mathrm{d}\NVar{x}}}
    C1.S4.SS4.m1aqdec
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    e {\displaystyle{\displaystyle\mathrm{e}}}
    C4.S2.E11.m2ajdec
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