DLMF:14.5.E6 (Q4718)

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DLMF:14.5.E6
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    𝖯 1 ( x ) = P 1 ( x ) = x . shorthand-Ferrers-Legendre-P-first-kind 1 𝑥 shorthand-Legendre-P-first-kind 1 𝑥 𝑥 {\displaystyle{\displaystyle\mathsf{P}_{1}\left(x\right)=P_{1}\left(x\right)=x% .}}
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    DLMF:14.5.E6
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