DLMF:24.6.E10 (Q7474)

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DLMF:24.6.E10
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    E n = 1 2 n k = 1 n + 1 ( n + 1 k ) j = 0 k - 1 ( - 1 ) j ( 2 j + 1 ) n . Euler-number-E 𝑛 1 superscript 2 𝑛 superscript subscript 𝑘 1 𝑛 1 binomial 𝑛 1 𝑘 superscript subscript 𝑗 0 𝑘 1 superscript 1 𝑗 superscript 2 𝑗 1 𝑛 {\displaystyle{\displaystyle E_{n}=\frac{1}{2^{n}}\sum_{k=1}^{n+1}{n+1\choose k% }\sum_{j=0}^{k-1}(-1)^{j}(2j+1)^{n}.}}
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    DLMF:24.6.E10
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