DLMF:15.4.E2 (Q4985)

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DLMF:15.4.E2
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    F ( 1 2 , 1 ; 3 2 ; z 2 ) = 1 2 z ln ( 1 + z 1 - z ) , Gauss-hypergeometric-F 1 2 1 3 2 superscript 𝑧 2 1 2 𝑧 1 𝑧 1 𝑧 {\displaystyle{\displaystyle F\left(\tfrac{1}{2},1;\tfrac{3}{2};z^{2}\right)=% \frac{1}{2z}\ln\left(\frac{1+z}{1-z}\right),}}
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    DLMF:15.4.E2
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