DLMF:15.4.E25 (Q5009)

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DLMF:15.4.E25
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    n = - Γ ( a + n ) Γ ( b + n ) Γ ( c + n ) Γ ( d + n ) = π 2 sin ( π a ) sin ( π b ) Γ ( c + d - a - b - 1 ) Γ ( c - a ) Γ ( d - a ) Γ ( c - b ) Γ ( d - b ) . superscript subscript 𝑛 Euler-Gamma 𝑎 𝑛 Euler-Gamma 𝑏 𝑛 Euler-Gamma 𝑐 𝑛 Euler-Gamma 𝑑 𝑛 superscript 𝜋 2 𝜋 𝑎 𝜋 𝑏 Euler-Gamma 𝑐 𝑑 𝑎 𝑏 1 Euler-Gamma 𝑐 𝑎 Euler-Gamma 𝑑 𝑎 Euler-Gamma 𝑐 𝑏 Euler-Gamma 𝑑 𝑏 {\displaystyle{\displaystyle\sum_{n=-\infty}^{\infty}\frac{\Gamma\left(a+n% \right)\Gamma\left(b+n\right)}{\Gamma\left(c+n\right)\Gamma\left(d+n\right)}=% \frac{\pi^{2}}{\sin\left(\pi a\right)\sin\left(\pi b\right)}\*\frac{\Gamma% \left(c+d-a-b-1\right)}{\Gamma\left(c-a\right)\Gamma\left(d-a\right)\Gamma% \left(c-b\right)\Gamma\left(d-b\right)}.}}
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    DLMF:15.4.E25
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