DLMF:18.22.E17 (Q5887)

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DLMF:18.22.E17
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    A ( x ) p n ( x + i ) - ( A ( x ) + C ( x ) ) p n ( x ) + C ( x ) p n ( x - i ) + 2 n sin ϕ p n ( x ) = 0 , 𝐴 𝑥 subscript 𝑝 𝑛 𝑥 𝑖 𝐴 𝑥 𝐶 𝑥 subscript 𝑝 𝑛 𝑥 𝐶 𝑥 subscript 𝑝 𝑛 𝑥 𝑖 2 𝑛 italic-ϕ subscript 𝑝 𝑛 𝑥 0 {\displaystyle{\displaystyle A(x)p_{n}(x+i)-\left(A(x)+C(x)\right)p_{n}(x)+C(x% )p_{n}(x-i)+2n\sin\phi\,p_{n}(x)=0,}}
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    DLMF:18.22.E17
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