DLMF:26.8.E21 (Q7849)

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DLMF:26.8.E21
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    s ( n + k + 1 , k ) = - j = 0 k ( n + j ) s ( n + j , j ) . Stirling-number-first-kind-S 𝑛 𝑘 1 𝑘 superscript subscript 𝑗 0 𝑘 𝑛 𝑗 Stirling-number-first-kind-S 𝑛 𝑗 𝑗 {\displaystyle{\displaystyle s\left(n+k+1,k\right)=-\sum_{j=0}^{k}(n+j)s\left(% n+j,j\right).}}
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    DLMF:26.8.E21
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