DLMF:27.7.E6 (Q8046)

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DLMF:27.7.E6
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    n = 1 λ ( n ) x n 1 - x n = n = 1 x n 2 . superscript subscript 𝑛 1 Liouville-lambda 𝑛 superscript 𝑥 𝑛 1 superscript 𝑥 𝑛 superscript subscript 𝑛 1 superscript 𝑥 superscript 𝑛 2 {\displaystyle{\displaystyle\sum_{n=1}^{\infty}\lambda\left(n\right)\frac{x^{n% }}{1-x^{n}}=\sum_{n=1}^{\infty}x^{n^{2}}.}}
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    DLMF:27.7.E6
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