DLMF:3.9.E6 (Q1391)

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DLMF:3.9.E6
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    π 4 = 1 - 1 3 + 1 5 - 1 7 + = 1 2 ( 1 + 1 ! 1 3 + 2 ! 3 5 + 3 ! 3 5 7 + ) . 4 1 1 3 1 5 1 7 1 2 1 1 1 3 2 3 5 3 3 5 7 {\displaystyle{\displaystyle\frac{\pi}{4}=1-\frac{1}{3}+\frac{1}{5}-\frac{1}{7% }+\cdots=\frac{1}{2}\left(1+\frac{1!}{1\cdot 3}+\frac{2!}{3\cdot 5}+\frac{3!}{% 3\cdot 5\cdot 7}+\cdots\right).}}
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    DLMF:3.9.E6
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    π {\displaystyle{\displaystyle\pi}}
    C3.S12.E1.m2adec
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