DLMF:4.6.E4 (Q1573)

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DLMF:4.6.E4
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    Statements

    ln z = 2 ( ( z - 1 z + 1 ) + 1 3 ( z - 1 z + 1 ) 3 + 1 5 ( z - 1 z + 1 ) 5 + ) , 𝑧 2 𝑧 1 𝑧 1 1 3 superscript 𝑧 1 𝑧 1 3 1 5 superscript 𝑧 1 𝑧 1 5 {\displaystyle{\displaystyle\ln z=2\left(\left(\frac{z-1}{z+1}\right)+\frac{1}% {3}\left(\frac{z-1}{z+1}\right)^{3}+\frac{1}{5}\left(\frac{z-1}{z+1}\right)^{5% }+\cdots\right),}}
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    DLMF:4.6.E4
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    z 0 𝑧 0 {\displaystyle{\displaystyle\Re z\geq 0}}
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    z 0 𝑧 0 {\displaystyle{\displaystyle\Re z\geq 0}}
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    z 0 𝑧 0 {\displaystyle{\displaystyle z\neq 0}}
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    ln z 𝑧 {\displaystyle{\displaystyle\ln\NVar{z}}}
    C4.S2.E2.m2acdec
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    absent {\displaystyle{\displaystyle\Re}}
    C1.S9.E2.m1aadec
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    z 𝑧 {\displaystyle{\displaystyle z}}
    C4.S1.XMD8.m1cdec
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