DLMF:14.15.E10 (Q4856)

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DLMF:14.15.E10
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    α ln ( ( α 2 + η 2 ) 1 / 2 + α ) - α ln η - ( α 2 + η 2 ) 1 / 2 = 1 2 ln ( ( 1 + α 2 ) x 2 + 1 - α 2 - 2 x ( α 2 x 2 - α 2 + 1 ) 1 / 2 ( x 2 - 1 ) ( 1 - α 2 ) ) + 1 2 α ln ( α 2 ( 2 x 2 - 1 ) + 1 + 2 α x ( α 2 x 2 - α 2 + 1 ) 1 / 2 1 - α 2 ) . 𝛼 superscript superscript 𝛼 2 superscript 𝜂 2 1 2 𝛼 𝛼 𝜂 superscript superscript 𝛼 2 superscript 𝜂 2 1 2 1 2 1 superscript 𝛼 2 superscript 𝑥 2 1 superscript 𝛼 2 2 𝑥 superscript superscript 𝛼 2 superscript 𝑥 2 superscript 𝛼 2 1 1 2 superscript 𝑥 2 1 1 superscript 𝛼 2 1 2 𝛼 superscript 𝛼 2 2 superscript 𝑥 2 1 1 2 𝛼 𝑥 superscript superscript 𝛼 2 superscript 𝑥 2 superscript 𝛼 2 1 1 2 1 superscript 𝛼 2 {\displaystyle{\displaystyle\alpha\ln\left(\left(\alpha^{2}+\eta^{2}\right)^{1% /2}+\alpha\right)-\alpha\ln\eta-\left(\alpha^{2}+\eta^{2}\right)^{1/2}=\frac{1% }{2}\ln\left(\frac{\left(1+\alpha^{2}\right)x^{2}+1-\alpha^{2}-2x\left(\alpha^% {2}x^{2}-\alpha^{2}+1\right)^{1/2}}{\left(x^{2}-1\right)\left(1-\alpha^{2}% \right)}\right)+\frac{1}{2}\alpha\ln\left(\frac{\alpha^{2}\left(2x^{2}-1\right% )+1+2\alpha x\left(\alpha^{2}x^{2}-\alpha^{2}+1\right)^{1/2}}{1-\alpha^{2}}% \right).}}
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    DLMF:14.15.E10
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    ln z 𝑧 {\displaystyle{\displaystyle\ln\NVar{z}}}
    C4.S2.E2.m2aadec
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    x 𝑥 {\displaystyle{\displaystyle x}}
    C14.S1.XMD1.m1gdec
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    α 𝛼 {\displaystyle{\displaystyle\alpha}}
    C14.S15.XMD3.m1fdec
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    η 𝜂 {\displaystyle{\displaystyle\eta}}
    C14.S15.XMD6.m1bdec
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