DLMF:24.16.E5 (Q7575)

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DLMF:24.16.E5
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    t ln ( 1 + t ) = n = 0 b n t n , 𝑡 1 𝑡 superscript subscript 𝑛 0 subscript 𝑏 𝑛 superscript 𝑡 𝑛 {\displaystyle{\displaystyle\frac{t}{\ln\left(1+t\right)}=\sum_{n=0}^{\infty}b% _{n}t^{n},}}
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    DLMF:24.16.E5
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    | t | < 1 𝑡 1 {\displaystyle{\displaystyle|t|<1}}
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    ln z 𝑧 {\displaystyle{\displaystyle\ln\NVar{z}}}
    C4.S2.E2.m2aadec
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    n 𝑛 {\displaystyle{\displaystyle n}}
    C24.S1.XMD5.m1ddec
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    t 𝑡 {\displaystyle{\displaystyle t}}
    C24.S1.XMD6.m1cdec
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