DLMF:19.19.E4 (Q6364)

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DLMF:19.19.E4
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    j = 1 n ( 1 + t z j ) = s = 0 n t s E s ( 𝐳 ) , superscript subscript product 𝑗 1 𝑛 1 𝑡 subscript 𝑧 𝑗 superscript subscript 𝑠 0 𝑛 superscript 𝑡 𝑠 subscript 𝐸 𝑠 𝐳 {\displaystyle{\displaystyle\prod_{j=1}^{n}(1+tz_{j})=\sum_{s=0}^{n}t^{s}E_{s}% (\mathbf{z}),}}
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    DLMF:19.19.E4
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    Warning: Falling back to standard tex;
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    n 𝑛 {\displaystyle{\displaystyle n}}
    C19.S1.XMD3.m1cdec
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