DLMF:26.13.E4 (Q7949)

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DLMF:26.13.E4
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    d ( n ) = n ! j = 0 n ( - 1 ) j 1 j ! = n ! + e - 2 e . 𝑑 𝑛 𝑛 superscript subscript 𝑗 0 𝑛 superscript 1 𝑗 1 𝑗 𝑛 2 {\displaystyle{\displaystyle d(n)=n!\sum_{j=0}^{n}(-1)^{j}\frac{1}{j!}=\left% \lfloor\frac{n!+\mathrm{e}-2}{\mathrm{e}}\right\rfloor.}}
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    DLMF:26.13.E4
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    e {\displaystyle{\displaystyle\mathrm{e}}}
    C4.S2.E11.m2adec
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