DLMF:17.2.E50 (Q5340)

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DLMF:17.2.E50
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    1 + n = 1 q n 2 + n ( 1 - q ) ( 1 - q 2 ) ( 1 - q n ) = n = 0 1 ( 1 - q 5 n + 2 ) ( 1 - q 5 n + 3 ) . 1 superscript subscript 𝑛 1 superscript 𝑞 superscript 𝑛 2 𝑛 1 𝑞 1 superscript 𝑞 2 1 superscript 𝑞 𝑛 superscript subscript product 𝑛 0 1 1 superscript 𝑞 5 𝑛 2 1 superscript 𝑞 5 𝑛 3 {\displaystyle{\displaystyle 1+\sum_{n=1}^{\infty}\frac{q^{n^{2}+n}}{(1-q)(1-q% ^{2})\cdots(1-q^{n})}=\prod_{n=0}^{\infty}\frac{1}{(1-q^{5n+2})(1-q^{5n+3})}.}}
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    DLMF:17.2.E50
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    Warning: Falling back to standard tex;
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    q 𝑞 {\displaystyle{\displaystyle q}}
    C17.S1.XMD10.m1avdec
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    n 𝑛 {\displaystyle{\displaystyle n}}
    C17.S1.XMD4.m1aodec
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