DLMF:2.6.E2 (Q827)

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DLMF:2.6.E2
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    ( 1 + t ) - 1 / 3 = s = 0 ( - 1 3 s ) t - s - ( 1 / 3 ) . superscript 1 𝑡 1 3 superscript subscript 𝑠 0 binomial 1 3 𝑠 superscript 𝑡 𝑠 1 3 {\displaystyle{\displaystyle(1+t)^{-1/3}=\sum_{s=0}^{\infty}\genfrac{(}{)}{0.0% pt}{}{-\frac{1}{3}}{s}t^{-s-(1/3)}.}}
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    DLMF:2.6.E2
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