DLMF:2.7.E3 (Q893)

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DLMF:2.7.E3
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    Q ( α ) α ( α - 1 ) + f 0 α + g 0 = 0 . equal-by definition 𝑄 𝛼 𝛼 𝛼 1 subscript 𝑓 0 𝛼 subscript 𝑔 0 0 {\displaystyle{\displaystyle Q(\alpha)\equiv\alpha(\alpha-1)+f_{0}\alpha+g_{0}% =0.}}
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    DLMF:2.7.E3
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