DLMF:10.19.E9 (Q3228)

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DLMF:10.19.E9
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    H ν ( 1 ) ( ν + a ν 1 3 ) H ν ( 2 ) ( ν + a ν 1 3 ) } 2 4 3 ν 1 3 e π i / 3 Ai ( e π i / 3 2 1 3 a ) k = 0 P k ( a ) ν 2 k / 3 + 2 5 3 ν e ± π i / 3 Ai ( e π i / 3 2 1 3 a ) k = 0 Q k ( a ) ν 2 k / 3 , asymptotic-expansion selection Hankel-H-1-Bessel-third-kind 𝜈 𝜈 𝑎 superscript 𝜈 1 3 Hankel-H-2-Bessel-third-kind 𝜈 𝜈 𝑎 superscript 𝜈 1 3 superscript 2 4 3 superscript 𝜈 1 3 superscript 𝑒 minus-or-plus 𝜋 𝑖 3 Airy-Ai superscript 𝑒 minus-or-plus 𝜋 𝑖 3 superscript 2 1 3 𝑎 superscript subscript 𝑘 0 shorthand-Legendre-P-first-kind 𝑘 𝑎 superscript 𝜈 2 𝑘 3 superscript 2 5 3 𝜈 superscript 𝑒 plus-or-minus 𝜋 𝑖 3 diffop Airy-Ai 1 superscript 𝑒 minus-or-plus 𝜋 𝑖 3 superscript 2 1 3 𝑎 superscript subscript 𝑘 0 shorthand-Legendre-Q-second-kind 𝑘 𝑎 superscript 𝜈 2 𝑘 3 {\displaystyle{\displaystyle\rselection{{H^{(1)}_{\nu}}\left(\nu+a\nu^{\frac{1% }{3}}\right)\\ {H^{(2)}_{\nu}}\left(\nu+a\nu^{\frac{1}{3}}\right)}\sim\frac{2^{\frac{4}{3}}}{% \nu^{\frac{1}{3}}}e^{\mp\pi i/3}\mathrm{Ai}\left(e^{\mp\pi i/3}2^{\frac{1}{3}}% a\right)\sum_{k=0}^{\infty}\frac{P_{k}\left(a\right)}{\nu^{2k/3}}+\frac{2^{% \frac{5}{3}}}{\nu}e^{\pm\pi i/3}\mathrm{Ai}'\left(e^{\mp\pi i/3}2^{\frac{1}{3}% }a\right)\sum_{k=0}^{\infty}\frac{Q_{k}\left(a\right)}{\nu^{2k/3}},}}
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    DLMF:10.19.E9
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