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  • and term-1: TeX pattern-expression " ( 1 + t ) - 1 / 3 = ∑ s = 0 ∞ ( - 1 3 s ) ⁢ t - s - ( 1 / 3 ) superscript 1 𝑡 1 3 superscript subscript 𝑠 0 binomial 1 3 𝑠 superscript 𝑡 𝑠 1 3 {\displaystyle{\displaystyle(1+t)^{-1/3}=\sum_{s=0}^{\infty}\genfrac{(}{)}{0.0% pt}{}{-\frac{1}{3}}{s}t^{-s-(1/3)}}} " with 0 results.

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