Formula:KLS:09.03:17: Difference between revisions

From DRMF
Jump to navigation Jump to search
imported>SeedBot
DRMF
 
m Move page script moved page Formula:KLS:09.03:17 to F:KLS:09.03:17
 
(No difference)

Latest revision as of 08:34, 22 December 2019


δ [ ω ( x ; a , b , c ) S n ( x 2 ; a , b , c ) ] δ x 2 = ω ( x ; a - 1 2 , b - 1 2 , c - 1 2 ) S n + 1 ( x 2 ; a - 1 2 , b - 1 2 , c - 1 2 ) 𝛿 delimited-[] 𝜔 𝑥 𝑎 𝑏 𝑐 continuous-dual-Hahn-normalized-S 𝑛 superscript 𝑥 2 𝑎 𝑏 𝑐 𝛿 superscript 𝑥 2 𝜔 𝑥 𝑎 1 2 𝑏 1 2 𝑐 1 2 continuous-dual-Hahn-normalized-S 𝑛 1 superscript 𝑥 2 𝑎 1 2 𝑏 1 2 𝑐 1 2 {\displaystyle{\displaystyle{\displaystyle\frac{\delta\left[\omega(x;a,b,c)S_{% n}\!\left(x^{2};a,b,c\right)\right]}{\delta x^{2}}{}=\omega(x;a-\textstyle% \frac{1}{2},b-\textstyle\frac{1}{2},c-\textstyle\frac{1}{2})S_{n+1}\!\left(x^{% 2};a-\textstyle\frac{1}{2},b-\textstyle\frac{1}{2},c-\textstyle\frac{1}{2}% \right)}}}

Substitution(s)

ω ( x ; a , b , c ) = 1 2 i x | Γ ( a + i x ) Γ ( b + i x ) Γ ( c + i x ) Γ ( 2 i x ) | 2 𝜔 𝑥 𝑎 𝑏 𝑐 1 2 imaginary-unit 𝑥 superscript Euler-Gamma 𝑎 imaginary-unit 𝑥 Euler-Gamma 𝑏 imaginary-unit 𝑥 Euler-Gamma 𝑐 imaginary-unit 𝑥 Euler-Gamma 2 imaginary-unit 𝑥 2 {\displaystyle{\displaystyle{\displaystyle\omega(x;a,b,c)=\frac{1}{2\mathrm{i}% x}\left|\frac{\Gamma\left(a+\mathrm{i}x\right)\Gamma\left(b+\mathrm{i}x\right)% \Gamma\left(c+\mathrm{i}x\right)}{\Gamma\left(2\mathrm{i}x\right)}\right|^{2}}}}


Proof

We ask users to provide proof(s), reference(s) to proof(s), or further clarification on the proof(s) in this space.

Symbols List

S n subscript 𝑆 𝑛 {\displaystyle{\displaystyle{\displaystyle S_{n}}}}  : continuous dual Hahn polynomial : http://dlmf.nist.gov/18.25#T1.t1.r3
i i {\displaystyle{\displaystyle{\displaystyle\mathrm{i}}}}  : imaginary unit : http://dlmf.nist.gov/1.9.i
Γ Γ {\displaystyle{\displaystyle{\displaystyle\Gamma}}}  : Euler's gamma function : http://dlmf.nist.gov/5.2#E1

Bibliography

Equation in Section 9.3 of KLS.

URL links

We ask users to provide relevant URL links in this space.