Formula:KLS:14.02:23

<< Formula:KLS:14.02:22

formula in q-Racah

Formula:KLS:14.02:24 >>

${\displaystyle{\displaystyle{\displaystyle\frac{\nabla\left[{\tilde{w}}(x;\alpha,\beta,\gamma,\delta|q)R_{n}\!\left(\mu(x);\alpha,\beta,\gamma,\delta\,|\,q\right)\right]}{\nabla\mu(x)}{}=\frac{1}{(1-q)(1-\gamma\delta)}{\tilde{w}}(x;\alpha q^{-1},\beta q^{-1},\gamma q^{-1},\delta|q){}R_{n+1}\!\left(\mu(x);\alpha q^{-1},\beta q^{-1},\gamma q^{-1},\delta\,|\,q\right)}}}$

Substitution(s)

${\displaystyle{\displaystyle{\displaystyle\mu(x)=q^{-x}+\gamma\delta q^{x+1}=\lambda(x)=q^{-x}+cq^{x-N}=q^{-x}+q^{x+\gamma+\delta+1}=2a\cos\theta}}}$ &

${\displaystyle{\displaystyle{\displaystyle\lambda(x)=x(x+\gamma+\delta+1)}}}$ &
${\displaystyle{\displaystyle{\displaystyle\mu(x):=q^{-x}+\gamma\delta q^{x+1}}}}$ &
${\displaystyle{\displaystyle{\displaystyle\mu(x)=q^{-x}+\gamma\delta q^{x+1}=\lambda(x)=q^{-x}+cq^{x-N}=q^{-x}+q^{x+\gamma+\delta+1}=2a\cos\theta}}}$ &

${\displaystyle{\displaystyle{\displaystyle\lambda(x)=x(x+\gamma+\delta+1)}}}$

Proof

We ask users to provide proof(s), reference(s) to proof(s), or further clarification on the proof(s) in this space.

Symbols List

& : logical and
${\displaystyle{\displaystyle{\displaystyle R_{n}}}}$ : ${\displaystyle{\displaystyle{\displaystyle q}}}$-Racah polynomial : http://dlmf.nist.gov/18.28#E19
${\displaystyle{\displaystyle{\displaystyle\mathrm{cos}}}}$ : cosine function : http://dlmf.nist.gov/4.14#E2

Bibliography

Equation in Section 14.2 of KLS.

URL links

We ask users to provide relevant URL links in this space.

<< Formula:KLS:14.02:22

formula in q-Racah

Formula:KLS:14.02:24 >>