DLMF:4.35.E22 (Q1896)

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DLMF:4.35.E22
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    tanh z 2 = ( cosh z - 1 cosh z + 1 ) 1 / 2 = cosh z - 1 sinh z = sinh z cosh z + 1 . 𝑧 2 superscript 𝑧 1 𝑧 1 1 2 𝑧 1 𝑧 𝑧 𝑧 1 {\displaystyle{\displaystyle\tanh\frac{z}{2}=\left(\frac{\cosh z-1}{\cosh z+1}% \right)^{1/2}=\frac{\cosh z-1}{\sinh z}=\frac{\sinh z}{\cosh z+1}.}}
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    DLMF:4.35.E22
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    cosh z 𝑧 {\displaystyle{\displaystyle\cosh\NVar{z}}}
    C4.S28.E2.m2aodec
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    sinh z 𝑧 {\displaystyle{\displaystyle\sinh\NVar{z}}}
    C4.S28.E1.m2andec
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    tanh z 𝑧 {\displaystyle{\displaystyle\tanh\NVar{z}}}
    C4.S28.E4.m2acdec
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    z 𝑧 {\displaystyle{\displaystyle z}}
    C4.S1.XMD8.m1edec
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