DLMF:17.2.E49 (Q5339)

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DLMF:17.2.E49
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    1 + n = 1 q n 2 ( 1 - q ) ( 1 - q 2 ) ( 1 - q n ) = n = 0 1 ( 1 - q 5 n + 1 ) ( 1 - q 5 n + 4 ) , 1 superscript subscript 𝑛 1 superscript 𝑞 superscript 𝑛 2 1 𝑞 1 superscript 𝑞 2 1 superscript 𝑞 𝑛 superscript subscript product 𝑛 0 1 1 superscript 𝑞 5 𝑛 1 1 superscript 𝑞 5 𝑛 4 {\displaystyle{\displaystyle 1+\sum_{n=1}^{\infty}\frac{q^{n^{2}}}{(1-q)(1-q^{% 2})\cdots(1-q^{n})}=\prod_{n=0}^{\infty}\frac{1}{(1-q^{5n+1})(1-q^{5n+4})},}}
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    DLMF:17.2.E49
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    Warning: Falling back to standard tex;
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    q 𝑞 {\displaystyle{\displaystyle q}}
    C17.S1.XMD10.m1audec
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    n 𝑛 {\displaystyle{\displaystyle n}}
    C17.S1.XMD4.m1andec
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