DLMF:19.9#Ex4 (Q6261)

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DLMF:19.9#Ex4
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    L = ( 1 / σ ) arctanh ( σ sin ϕ ) , 𝐿 1 𝜎 hyperbolic-inverse-tangent 𝜎 italic-ϕ {\displaystyle{\displaystyle L=(1/\sigma)\operatorname{arctanh}\left(\sigma% \sin\phi\right),}}
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    DLMF:19.9#Ex4
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    σ = ( 1 + k 2 ) / 2 𝜎 1 superscript 𝑘 2 2 {\displaystyle{\displaystyle\sigma=\sqrt{(1+k^{2})/2}}}
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