DLMF:19.12#Ex1 (Q6300)

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DLMF:19.12#Ex1
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    d ( m ) = ψ ( 1 + m ) - ψ ( 1 2 + m ) , 𝑑 𝑚 digamma 1 𝑚 digamma 1 2 𝑚 {\displaystyle{\displaystyle d(m)=\psi\left(1+m\right)-\psi\left(\tfrac{1}{2}+% m\right),}}
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    DLMF:19.12#Ex1
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